a curling rock with a mass 22 kg is traveling 0 degrees at 3m/s and collides with a stationary object with the same mass the collision is a glancing one and the struck roce is moving 1m/s at 65 degrees what is the velocity after the collision

The final momentum is 22*3 kg m/s

you are given one objects mass, velocity after collision.
for that object, zero deg momentum is 22*1*cos65
subtract that from the initial momentum at zero, and you have the zero deg momentum of rock 2.

Now the other direction>
at 90 deg, the moving rock momentum is 22*1*sin65
the other rock must be moving then at momentum 22^1*sin(180+65)

now, you can find the velocity and direction of the original rock after collision, you have two components at ninety degrees.

To find the velocity of the curling rock after the collision, we can use the principles of conservation of momentum. Momentum is defined as the product of mass and velocity.

1. Write down the initial momentum before the collision. Momentum is a vector quantity, so we need to consider both the magnitude and direction. Let's call the initial momentum P_initial.

P_initial = (mass of curling rock) x (velocity of curling rock)
= 22 kg x 3 m/s (since the curling rock is traveling at 0 degrees)

2. Write down the momentum after the collision. Again, considering both the magnitude and direction. Let's call the final momentum P_final.

P_final = (mass of curling rock) x (velocity of struck rock)
= 22 kg x 1 m/s (since the struck rock is moving at 65 degrees)

3. Now, use the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

P_initial = P_final

Substituting the values we have,

22 kg x 3 m/s = 22 kg x 1 m/s

4. Solve for the velocity of the curling rock after the collision.

(22 kg x 3 m/s) / 22 kg = 1 m/s

The velocity of the curling rock after the collision is 1 m/s.