Story Problem - Factoring
An "A" train leaves a subway station every 13 minutes. An "E" train leaves evry 9 minutes. If both trains just left the station on parallel tracts, when will both leave the station together again?
One hundred seventeen mins.
And Alisson, you just copied and pasted what Steve wrote.
Ur all wrong 177 is not even an answer choice. Im on the same quiz the options are
A. 108
B. 36
C. 72
D. 24
And idk what the answer is
I agree
To find out when both trains will leave the station together again, you need to find the least common multiple (LCM) of the two time intervals - 13 minutes for the "A" train and 9 minutes for the "E" train. The LCM represents the smallest possible number that is evenly divisible by both 13 and 9.
Here's how you can find the LCM:
1. List the multiples of each number until you find a common multiple:
For the "A" train: 13, 26, 39, 52, 65, 78, 91, ...
For the "E" train: 9, 18, 27, 36, 45, 54, 63, 72, 81, 90, ...
2. Look for the first common multiple of 13 and 9:
The first common multiple you find is 117 (13 x 9 = 117), so this is the least common multiple (LCM).
Therefore, both the "A" and "E" trains will leave the station together again in 117 minutes.
Since LCM(9,13) = 9*13 = 117
After 117 minutes,
9 A trains will have left,
13 E trains will have left
and then the cycle starts over.
Trains run on tracks, not tracts.
117minutes
Since LCM(9,13) = 9*13 = 117
After 117 minutes,
9 A trains will have left,
13 E trains will have left
and then the cycle starts over.
Trains run on tracks, not tracts. ~Alisson~