physics

Cliff divers at Acapulco jump into the sea from a cliff 37.1 m high. At the level of the sea, a rock sticks out a horizontal distance of13.39 m. The acceleration of gravity is 9.8 m/s^2. With what minimum horizontal velocity must the cliff divers leave the top of the cliff if they are to miss the rock?

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asked by emma
  1. h = Vo*t + 0.5g*t^2 = 37.1 m.
    0 + 4.9t^2 = 37.1
    t^2 = 7.57
    t = 2.75 s.

    d = V*t = 13.9 m.
    2.75V = 13.9
    V = 5.05 m/s.

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    posted by Henry

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