if 3 resistors of 2,3 and 5 ohms are connected in parallel and a battery of 10 volts is applied across it, then what is the potential drop across 3 ohms resistor ?
If they are in parallel, the voltage across them is 10 volts.
To find the potential drop across the 3-ohm resistor in a parallel circuit, we need to use Ohm's Law and the concept of equivalent resistance.
First, let's calculate the equivalent resistance (Req) of the parallel circuit. In a parallel circuit, the reciprocal of the equivalent resistance is equal to the sum of the reciprocals of the individual resistances. Mathematically, it can be represented as:
1/Req = 1/R1 + 1/R2 + 1/R3
Given that R1 = 2 ohms, R2 = 3 ohms, and R3 = 5 ohms, substituting these values into the equation, we have:
1/Req = 1/2 + 1/3 + 1/5
Now, calculate the equivalent resistance by taking the reciprocal of both sides:
Req = 1 / (1/2 + 1/3 + 1/5)
Next, use Ohm's Law (V = I * R) to find the current (I) in the circuit. Ohm's Law states that the voltage (V) across a resistor is equal to the current (I) flowing through it multiplied by the resistance (R). In a parallel circuit, the voltage remains the same across all resistors.
Since we have a battery voltage of 10 volts applied across the circuit, the voltage across the 3-ohm resistor will also be 10 volts.
So, the potential drop across the 3-ohm resistor is 10 volts.