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precalculus
Can you please check my answers? 1.Find Pk + 1 if Pk=2^K1/k! answer: 2^k+1/(k+1)! 2.Find Pk + 1 if Pk = 7 + 13 + 19 + ...+[6(k  1)+1] + (6k + 1) answer: 7+13+9...(6k1+1)+6k+1 +(6k+2) 3.What is the first step when writing a
asked by Anonymous on December 14, 2016 
precalculus
Find Pk + 1 if Pk = 7 + 13 + 19 + ...+[6(k  1)+1] + (6k + 1) 7 + 13 + 19 + …+[6(k  1) + 1] + (6k + 1) + [6(k + 1) + 1] 8 + 14 + 20 + …+[7(k  1) + 1] + (7k + 1) 7 + 13 + 19 + …+(6k + 1) 7 + 13 + 19 + ...+[6(k  1) + 1] +
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Use mathematical induction to prove that the statement holds for all positive integers. Also, label the basis, hypothesis, and induction step. 1 + 5 + 9 + … + (4n 3)= n(2n1)
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Use mathematical induction to prove that the statement holds for all positive integers. Also, can you label the basis, hypothesis, and induction step in each problem. Thanks 1. 2+4+6+...+2n=n^2+n 2. 8+10+12+...+(2n+6)=n^2+7n
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Can you check my answers? 1.Which of the following shows the best next step to prove the following by mathematical induction? 3^n>n*2^n, n≥1 1.When n=1, the formula is valid because 3^1 1*2^1 3>2 2.Assuming that 3^k>k*2^k
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Prove by mathematical induction that 1+3+5+7+....+(2n1)=n²
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use mathematical induction to prove 1/2^n = 1/2^n  1
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