CH4(g) + 2O2(g) = CO2(g) + 2H20(g). What volume of O2 is required to react with 2.0 mol CH4 at 50 degrees Celsius and .500 atm?

At STP volume oxygen is

volume O2 = 2.0 mol CH4 x (2 mols O2/1 mol CH4) = 2*2/1 = 4 mols O2.
Use PV = nRT to convert to L at the conditions of the problem.