What is the maximum mass of H2O that can be produced by combining 90.8 g of each reactant
Write the equation and balance it.
mols H2 = grams/molar mass
mols O2 = grams/molar mass
Convert mols H2 to mols product.
Do the same for O2.
The smaller number of mols wins; that will be the mols H2O produced. Then mol x molar mass H2O = grams H2O.
To determine the maximum mass of H2O that can be produced by combining 90.8 g of each reactant, you need to calculate the limiting reactant. This reactant determines the maximum amount of product that can be formed.
Assuming the reactants are hydrogen gas (H2) and oxygen gas (O2), the balanced chemical equation for the formation of water (H2O) is:
2H2 + O2 → 2H2O
The molar mass of H2O is 18.015 g/mol.
Step 1: Calculate the number of moles for each reactant.
Number of moles of H2 = Mass of H2 / Molar mass of H2 = 90.8 g / 2 g/mol = 45.4 mol
Number of moles of O2 = Mass of O2 / Molar mass of O2 = 90.8 g / 32 g/mol = 2.84 mol
Step 2: Determine the limiting reactant.
According to the balanced equation, the ratio of the reactants is 2:1 (2 moles of H2 react with 1 mole of O2). Therefore, the O2 is the limiting reactant since there is not enough O2 to react with all of the H2.
Step 3: Calculate the maximum mass of H2O that can be produced.
The limiting reactant (O2) will determine the maximum number of moles of H2O that can be produced. Since the balanced equation shows that 2 moles of H2O are formed for every 1 mole of O2, the maximum moles of H2O formed will be half the moles of the limiting reactant.
Number of moles of H2O = 0.5 * Number of moles of O2 = 0.5 * 2.84 mol = 1.42 mol
Step 4: Calculate the maximum mass of H2O.
Mass of H2O = Number of moles of H2O * Molar mass of H2O = 1.42 mol * 18.015 g/mol = 25.5833 g
Therefore, the maximum mass of H2O that can be produced by combining 90.8 g of each reactant is approximately 25.6 g.
To determine the maximum mass of H2O produced, we first need to identify the balanced chemical equation for the reaction where H2O is produced.
The balanced equation for the formation of water (H2O) from its reactant molecules (H2 and O2) is:
2H2(g) + O2(g) -> 2H2O(g)
From the balanced chemical equation, we can see that two moles of H2 react with one mole of O2 to produce two moles of H2O.
To calculate the maximum mass of H2O produced, we need to follow these steps:
Step 1: Convert the mass of each reactant (90.8 g) to moles.
To do this, we need the molar mass of each reactant. The molar mass of H2 is 2.02 g/mol, and the molar mass of O2 is 32.00 g/mol.
Number of moles of H2 = mass of H2 / molar mass of H2
Number of moles of H2 = 90.8 g / 2.02 g/mol = 45.05 mol
Number of moles of O2 = mass of O2 / molar mass of O2
Number of moles of O2 = 90.8 g / 32.00 g/mol = 2.84 mol
Step 2: Determine the limiting reactant.
The limiting reactant is the one present in lesser amount, which restricts the amount of product that can be formed. To determine it, we need to compare the moles of each reactant to the stoichiometric ratio in the balanced equation.
From the balanced equation, we see that 2 moles of H2 react with 1 mole of O2. This means that the ratio of H2 to O2 is 2:1.
Ratio of moles H2 to O2 = moles of H2 / moles of O2
Ratio of moles H2 to O2 = 45.05 mol / 2.84 mol = 15.86
Since the ratio is greater than 2:1, we can conclude that H2 is in excess and O2 is the limiting reactant.
Step 3: Calculate the moles of H2O formed.
Since H2 and O2 react in a 2:1 ratio to form H2O, the moles of H2O formed will be equal to the moles of O2 used.
Number of moles of H2O = Number of moles of O2 = 2.84 mol
Step 4: Convert the moles of H2O to grams.
To convert moles of H2O to grams, we need the molar mass of H2O. The molar mass of H2O is 18.02 g/mol.
Mass of H2O = Number of moles of H2O * molar mass of H2O
Mass of H2O = 2.84 mol * 18.02 g/mol = 51.17 g
Therefore, the maximum mass of H2O that can be produced by combining 90.8 g of each reactant is 51.17 grams.