Hi! Can someone please balance these equations, please?! I'm having major trouble! Thank you!
HCl (aq) + NaHCO3 (aq) �¨
HBr (aq) + NH3 (aq) �¨
LiHCO3 (aq) + HI (aq) �¨
Is your problem with balancing or is it with naming the products?
HCl(aq) + NaHCO3(aq) ==> H2O(l) + CO2(g) + NaCl(aq)
HBr(aq) + NH3(aq) ==> NH4Br(aq)
LiHCO3(aq) + HI(aq) ==> LiI(aq) + H2O(l) + CO2(g)
Of course! I can assist you with balancing these equations. To balance a chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Let's balance these equations step by step:
1. HCl (aq) + NaHCO3 (aq) →
We have one hydrogen (H) atom on the left and one on the right, so it's already balanced. Let's move on to balancing the other elements.
Next, we have one chlorine (Cl) atom on the left, but no chlorine on the right. So, we need to add a coefficient to HCl to balance the chlorines. Let's place a coefficient of 1 in front of HCl.
HCl (aq) + NaHCO3 (aq) →
Now let's balance the sodium (Na) atoms. There is one sodium atom on the right and one sodium atom on the left, so that is already balanced.
HCl (aq) + NaHCO3 (aq) →
Now let's balance the carbon (C) atoms. There is one carbon atom on the right and one carbon atom on the left, so no further changes are needed.
HCl (aq) + NaHCO3 (aq) →
Now, let's balance the oxygen (O) atoms. On the left side, we have three oxygen atoms from NaHCO3, but on the right side, we only have one oxygen atom from HCl. To balance the oxygens, we need to add a coefficient of 3 in front of HCl.
3 HCl (aq) + NaHCO3 (aq) →
Now the final balanced equation is:
3 HCl (aq) + NaHCO3 (aq) → NaCl (aq) + H2O (l) + CO2 (g)
2. HBr (aq) + NH3 (aq) →
First, let's balance the hydrogen (H) atoms. We have one hydrogen on both sides, so that is already balanced.
HBr (aq) + NH3 (aq) →
Next, let's balance the bromine (Br) atoms. There is one bromine atom on the left from HBr, so we need to add a coefficient of 1 in front of NH3 to balance the bromines.
HBr (aq) + 1 NH3 (aq) →
Now, let's balance the nitrogen (N) atoms. There is one nitrogen atom on both sides, so no further changes are needed.
HBr (aq) + 1 NH3 (aq) →
Finally, let's balance the hydrogen (H) atoms again since we made a change. There is one hydrogen atom on the left and three hydrogen atoms on the right, so we need to add a coefficient of 3 in front of HBr to match the number of hydrogens.
3 HBr (aq) + 1 NH3 (aq) →
The balanced equation is:
3 HBr (aq) + NH3 (aq) → 3 H2O (l) + N2 (g)
3. LiHCO3 (aq) + HI (aq) →
First, let's balance the lithium (Li) atoms. We have one lithium on the left and none on the right, so we need to add a coefficient of 1 in front of HI to balance the lithium.
LiHCO3 (aq) + 1 HI (aq) →
Next, let's balance the hydrogen (H) atoms. We have one hydrogen on the left from HI and only one hydrogen on the right, so that is already balanced.
LiHCO3 (aq) + 1 HI (aq) →
Now, let's balance the carbon (C) atoms. There is one carbon on the left from LiHCO3, so we need to add a coefficient of 1 in front of HI to balance the carbon.
LiHCO3 (aq) + 1 HI (aq) →
Finally, let's balance the oxygen (O) atoms. We have three oxygen atoms on the left and one oxygen atom on the right, so we need to add a coefficient of 3 in front of HI to balance the oxygens.
LiHCO3 (aq) + 3 HI (aq) →
The balanced equation is:
LiHCO3 (aq) + 3 HI (aq) → LiI (aq) + 3 H2O (l) + CO2 (g)
I hope this helps! Let me know if you have any further questions.