2 SO2 (g)+O2 (g)→2 SO3­↑

How many grams of SO3(g) are formed if 8.45 grams of oxygen are used?

To determine the number of grams of SO3(g) formed, you first need to set up a stoichiometry calculation using the balanced equation.

1. Start by writing the balanced equation: 2 SO2(g) + O2(g) -> 2 SO3(g)

2. Determine the molar mass of O2 by adding up the atomic masses of oxygen (O). The atomic mass of O is 16.00 g/mol, so the molar mass of O2 is 2 * 16.00 g/mol = 32.00 g/mol.

3. Use the molar ratio between O2 and SO3. From the balanced equation, you can see that the ratio between O2 and SO3 is 1:2. This means that for every 1 mole of O2, 2 moles of SO3 are produced.

4. Convert grams of O2 to moles using its molar mass. Divide the given mass (8.45 g) by the molar mass of O2 (32.00 g/mol):

moles of O2 = 8.45 g / 32.00 g/mol = 0.264 moles of O2

5. Determine the moles of SO3 produced using the molar ratio from step 3. Since the ratio is 1:2, multiply the moles of O2 by 2 to get the moles of SO3:

moles of SO3 = moles of O2 * 2 = 0.264 mol * 2 = 0.528 moles of SO3

6. Finally, convert moles of SO3 to grams using its molar mass. The molar mass of SO3 is 32.07 g/mol:

grams of SO3 = moles of SO3 * molar mass of SO3 = 0.528 mol * 32.07 g/mol = 16.930 g

Therefore, 8.45 grams of oxygen will produce 16.930 grams of SO3.

To find the number of grams of SO3(g) formed, we need to use stoichiometry and the given balanced equation.

First, let's find the balanced equation for the reaction:

2 SO2(g) + O2(g) → 2 SO3(g)

According to the balanced equation, we can see that for every 1 mole of O2 consumed, 2 moles of SO3 are formed.

Next, we need to calculate the number of moles of O2(g) used based on the given mass of oxygen. We can do this by using the molar mass of oxygen, which is 32 g/mol:

moles of O2 = mass of oxygen / molar mass of O2
moles of O2 = 8.45 g / 32 g/mol

Now, let's calculate the moles of SO3 formed using the mole ratio from the balanced equation:

moles of SO3 = moles of O2 × 2

Finally, we can convert moles of SO3 to grams by multiplying it by the molar mass of SO3, which is 80 g/mol:

mass of SO3 = moles of SO3 × molar mass of SO3

By plugging in the calculated values, we can find the answer to the question.

mols O2 = grams/molar mass.

Using the coefficients in the balanced equation, convert mols O2 to mols SO3.
Now convert mols SO3 t grams. g = mols x molar mass.