Currently studying for an lab exam. Just have a few question about a typical Iodine Clock reaction lab.

In an typical Iodine Clock reaction lab what would be the state of effect of an increase in the initial concentration of persulfate ion and the increase in the initial concentration of iodide ion?

If the thiosulfate ion solution was omitted what would appear in the solution?
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yes

In a typical Iodine Clock reaction lab, an increase in the initial concentration of persulfate ion and an increase in the initial concentration of iodide ion will have different effects on the reaction.

1. Increase in the initial concentration of persulfate ion: Persulfate ion (S2O8^-2) acts as the oxidizing agent in the reaction and reacts with iodide ion (I^-) to form iodine (I2). So, increasing the concentration of persulfate ion will result in a higher rate of production of iodine molecules. This would speed up the reaction and decrease the time taken for the reaction to reach a certain color change or endpoint.

2. Increase in the initial concentration of iodide ion: Iodide ion (I^-) acts as the reducing agent in the reaction and reacts with persulfate ion (S2O8^-2) to form iodine (I2). Increasing the concentration of iodide ion will result in a higher rate of formation of iodine molecules. Similar to the effect of persulfate ion, increasing the initial concentration of iodide ion will also speed up the reaction and decrease the time taken to reach the color change or endpoint.

If the thiosulfate ion solution was omitted from the reaction, the reaction will not have a substance capable of reducing iodine back to iodide. Thiosulfate ion (S2O3^-2) is typically added to the reaction mixture as a titrant to react with excess iodine produced during the reaction. This reaction converts iodine back to iodide, which prevents the color change from occurring prematurely.

Without the thiosulfate ion, the solution would not have a means to convert the iodine back to iodide. As a result, iodine will remain in the solution, which is typically brownish in color. This would lead to an incomplete reaction and potentially inaccurate results.

To obtain a definitive answer to your question, I would suggest referring to your lab manual or consulting with your instructor, as specific experimental conditions may vary.