im getting rele confused on this. ok here is the prob.


equation 1 x+y=5
equation 2 x-2y=-4

Multiply equation 1 by -1.
Add equation 1 to equation 2. The x term cancels. Solve for y.

THEN, put the value of y into either equation and solve for x.

Finally, put the value of x and y into the OTHER equation and see if those values satisfy the equation.

  1. 👍 0
  2. 👎 0
  3. 👁 145
asked by Tony
  1. Multiplying Equation 1 by -1 you get:


    Adding that to equation 2 you get:

    -x -y = -5
    + x -2y = -4
    -3y = -9
    Divide both sides by -3 and you get
    Put that back into either equation and you can solve for x
    So x=2, y=3 should be the solutions.
    Check this in the other equation, x-2y=-4
    2-2(3) = -4
    2-6 = -4 why yes it does! :-)

    1. 👍 0
    2. 👎 0
    posted by Anon
  2. what

    1. 👍 0
    2. 👎 0
    posted by new moon

Respond to this Question

First Name

Your Response

Similar Questions

  1. math

    actually, in a addition to the question i posted a few minutes ago, can someone please help me with a few actual specific questions? thanks so much i'm very confused and i've been working on these all day. *Literal Equations*

    asked by kim on October 26, 2007
  2. Math

    ok so i'm kinda sort of confused... I had this for a equation X^2 + 4X - 1 = 0 and then I was like zero??? zero... really zero... hmm... X^2 + 4X - 1 = dy ???????? That zero does represent when Y equals zero correct??? this allows

    asked by Kate on January 3, 2010
  3. Algebra

    Hey! I like math,but this year I'm doing algebra 1 and am not doing so well. I understand the lessons,but then the next day I learn a new way to solve a different problem and confuse the old way with this new way. So on tests,I

    asked by Lis on March 12, 2008
  4. math

    just an algebra question. how would you solve: (3x^2 +5)(3x^2 +5) ^ means power :] Since you have not given us an equation, it is impossible to "solve" your problam. Please repost with the complete equation, so we can help you. I

    asked by Kelly on September 5, 2006
  5. help!

    A horizontal translation is applied to the graph of y= X^ 3 + 2 so that it will pass through (3, 10) what is the new equation for the graph? how do I do this? When x=3, one wants y to be 10 y= (x+a)^3 + 2 20= (3+a)^3 + 2 solve for

    asked by kris on August 28, 2006
  6. Math, Please Help! I don't understand!

    I need help because I don't understand how to solve this equation. 37. x/a - 1 = y/b for x So... does it mean solve for x? 39. V = 1/3 * pi * radius^2 * h for h So... does it mean solve for h? As you can see, I am really confused.

    asked by Alexandra on November 4, 2014
  7. Math

    Solve for S: r^2s-5s=7. Solve for b: L= 4a^2b. I'm confused about how to solve these problems. Could someone show me the steps?

    asked by Sue on September 12, 2011
  8. college algebra

    Solve the following inequality. x^3+9x^2-108 less or equal to 0. Then write your solution in interval notation. I am sooo confused and do not have any idea how to do this. Can someone please show me step by step please??? Thanks

    asked by allison-please help!!! on December 25, 2012
  9. Math

    Use properties of equality and numbers to solve each equation for x. A. 7+3x = 5x + 13 how am i suppose to solve i am kind of confused?!?!

    asked by EmilyMay on April 3, 2012
  10. Math, Please Help! I don't understand!

    Please help me! I don't understand how to solve. Solve each equation for the given variable. 37. x/a - 1 = y/b for x 39. V = 1/3 * pi * r^2 * h for h What do these equations mean? I am super confused. Please help.

    asked by Hayden on October 31, 2014

More Similar Questions