An object is dropped from a height of 49 meters. The object takes 3.2s to hit the ground. The final velocity of the object when it hits the ground is 31 m/s
Vo = 0 = Initial velocity.
V = 31 m/s. = Final velocity.
T = 3.2 s.
d = 49 m.
g = 9.8 m/s^2.
Everything is given. So what is the unknown or question?
To find the acceleration due to gravity (g) we can use the equation of motion:
v^2 = u^2 + 2as
Where:
v = final velocity (31 m/s)
u = initial velocity (0 m/s, as the object was dropped)
s = displacement (falling distance, 49 meters)
a = acceleration due to gravity (unknown)
Rearranging the equation and substituting the known values, we get:
31^2 = 0^2 + 2 * a * 49
961 = 0 + 98a
Simplifying, we find:
98a = 961
a = 961 / 98
a ≈ 9.8163 m/s^2
Therefore, the acceleration due to gravity is approximately 9.8163 m/s^2.