The top of a rectangular dining room table is twice as long as it is wide. dimensions of the table if the area is 72 ft^2

the table is_____ft wide and ______ ft. long.

PLEASE HELP

To find the dimensions of the table, let's use the given information and the formula for the area of a rectangle:

Area = Length * Width

Given:

Length = 2 * Width
Area = 72 ft^2

Let's substitute the value of Length in terms of Width into the area formula:

72 = (2 * Width) * Width

Simplifying the equation:

72 = 2 * Width^2

Divide both sides by 2:

36 = Width^2

Taking the square root of both sides:

Width = √36
Width = 6 ft

Now, we can find the Length using the equation:

Length = 2 * Width
Length = 2 * 6
Length = 12 ft

Therefore, the table is 6 ft wide and 12 ft long.

To find the dimensions of the dining room table, we can start by setting up an equation based on the information given.

Let's say the width of the table is represented by "w" feet. According to the problem, the length of the table is twice as long as the width, so the length would be "2w" feet.

The area of a rectangle can be calculated by multiplying the length and width. In this case, the area is given as 72 square feet, so we can set up the equation:

Area = length × width
72 = 2w × w

Now, we can solve the equation by factoring or by setting it equal to zero and using the quadratic formula, but in this case, we can simplify it further. Since we already know that the area is 72 square feet, we can divide both sides of the equation by 2:

36 = w^2

Now, we can take the square root of both sides to solve for "w":

√36 = √(w^2)
6 = w

So, the width of the table is 6 feet. Since the length is twice as long as the width, the length would be:

2w = 2 × 6 = 12 feet.

Therefore, the table is 6 feet wide and 12 feet long.

X Ft. = Width.

2x Ft. = Length.

A = L * W = 2x * x = 2x^2 = 72Ft^2.
2x^2 = 72
x^2 = 36
X = 6 Ft = Width.
2X = 12 Ft. = Length.