An artificial sattelite as a mars of 600 kg and moving towards moon.calculate its kinetic energy and potential energy in mJ relative to the earth when it is 50 km from launching and moving at 2500 km/h take acceleration of earth gravitational field as 790 cm/s*s

KE=1/2 *600*v^2 convert 2500km/hr to m/s

Now on PE, I am troubled by your graviational field. You list it as constant, however, if it is relative to earth, that field changes nearer Earth, by a significant factor, so PE relative to Earth is more than a constant field would indicate.

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To calculate the kinetic energy and potential energy of the satellite relative to Earth, we need to know the formulas for both types of energy.

1. Kinetic Energy (KE):
The formula for kinetic energy is KE = 0.5 * mass * velocity^2.

2. Potential Energy (PE):
The formula for potential energy near the Earth's surface is PE = mass * acceleration due to gravity * height.

Now let's calculate each energy type:

1. Kinetic Energy (KE):
Given:
Mass of the satellite (m) = 600 kg
Velocity of the satellite (v) = 2500 km/h = 2500 * (1000/3600) m/s = 694.44 m/s

Using the formula: KE = 0.5 * m * v^2
KE = 0.5 * 600 * 694.44^2

Calculating this, we find:
KE ≈ 145,972,960 J

Converting to millijoules (mJ):
1 Joule (J) = 1000 millijoules (mJ)
So, KE ≈ 145,972.96 mJ

Therefore, the kinetic energy of the satellite is approximately 145,972.96 mJ.

2. Potential Energy (PE):
Given:
Mass of the satellite (m) = 600 kg
Height (h) = 50 km = 50 * 1000 m = 50,000 m
Acceleration due to gravity (g) = 790 cm/s^2 = 7.9 m/s^2

Using the formula: PE = m * g * h
PE = 600 * 7.9 * 50,000

Calculating this, we find:
PE = 237,000,000 J

Converting to millijoules (mJ):
PE = 237,000,000 * 1000

Therefore, the potential energy of the satellite is 237,000,000,000 mJ.

Note: The potential energy value seems quite large because the height in this calculation is measured from the Earth's surface, and it increases as the satellite moves away from Earth.