find the heat energy needed to change 200 g of water at 4c to water at 88c

q = mass x specific heat x (Tfinal-Tinitial)

To find the heat energy needed to change the temperature of water from 4°C to 88°C, you can use the formula:

Q = m * c * ΔT

where:
Q is the heat energy (in Joules),
m is the mass of water (in grams),
c is the specific heat capacity of water (4.184 J/g°C),
ΔT is the change in temperature (in °C).

Let's plug in the values:

m = 200 g
c = 4.184 J/g°C
ΔT = (88°C - 4°C) = 84°C

Q = 200 g * 4.184 J/g°C * 84°C
Q = 703,296 J

Therefore, the heat energy needed to change 200 g of water at 4°C to water at 88°C is 703,296 Joules.

To find the heat energy needed to change the temperature of water, you can use the equation:

Q = m * c * ΔT

where:
Q is the heat energy (in joules)
m is the mass of the substance (in grams or kilograms)
c is the specific heat capacity of the substance (in J/g°C or J/kg°C)
ΔT is the change in temperature (in °C)

Let's break it down step by step:

1. Mass of water (m):
Given: m = 200 g

2. Change in temperature (ΔT):
To find the change in temperature, subtract the initial temperature from the final temperature:
Given initial temperature (T1) = 4°C
Given final temperature (T2) = 88°C

ΔT = T2 - T1
= 88°C - 4°C
= 84°C

3. Specific heat capacity of water (c):
The specific heat capacity of water is approximately 4.18 J/g°C.

4. Calculating the heat energy (Q):
Q = m * c * ΔT
= 200 g * 4.18 J/g°C * 84°C

Now, let's calculate the answer:

Q = 200 g * 4.18 J/g°C * 84°C

Q ≈ 70,896 J

Therefore, the heat energy needed to change 200 g of water at 4°C to water at 88°C is approximately 70,896 Joules.