A saturated solution of NaCl (dissolved in water) has a concentration of 4.01 M at a given temperature. The solution has a volume of 1 L (1000 mL). If the water were to evaporate until the volume of the solution is 500 mL (and then stirred), what would the concentration of the new solution be?

To find the concentration of the new solution, we need to use the concept of molarity and understand the relationship between concentration, volume, and amount of solute.

Let's break down the problem step by step:

1. Calculate the amount of solute (NaCl) in the original solution.
Since the concentration is given as 4.01 M and the volume is 1 L, we can use the formula:
Amount of solute = Concentration x Volume

Amount of solute = 4.01 M x 1 L = 4.01 moles of NaCl

2. Determine the new volume of the solution after evaporation.
The volume is reduced to 500 mL or 0.5 L.

3. Calculate the new concentration of the solution.
We'll use the amount of solute (4.01 moles) and the new volume (0.5 L) to find the concentration.
Concentration = Amount of solute / Volume

Concentration = 4.01 moles / 0.5 L = 8.02 M

Therefore, after evaporation and stirring, the concentration of the new solution would be 8.02 M.

4.01M = 4.01 mols/L soln.

If half of the water is evaporated you now have the same number of mols in 0.5L so 4.01mol/0.5L =?M