Ni(NO3)2.H2O+2KSCN

WHAT IS THE PRODUCT?? WHAT COMPLEX IS FORMED ?

To determine the product and the complex formed, we need to understand the reaction that is taking place between Ni(NO3)2.H2O (nickel nitrate hexahydrate) and KSCN (potassium thiocyanate).

The reaction between Ni(NO3)2.H2O and KSCN is a double displacement reaction. The general equation for this type of reaction is:

AB + CD → AD + CB

In this case:

Ni(NO3)2.H2O + 2KSCN → Ni(SCN)2 + 2KNO3 + 2H2O

The products of this reaction are Ni(SCN)2 (nickel thiocyanate), KNO3 (potassium nitrate), and H2O (water).

Now let's determine the complex formed. A complex is formed when a metal ion (in this case, Ni2+) is surrounded by ligands (in this case, SCN-). The complex formed in this reaction is Ni(SCN)2. It consists of a central nickel ion (Ni2+) and two thiocyanate ions (SCN-) as ligands.

Therefore, the product of the reaction is Ni(SCN)2, and it forms a complex called nickel thiocyanate.

It is important to note that the presence of water in the reactant (Ni(NO3)2.H2O) does not affect the product or the complex formed. The water molecules are used to indicate that nickel nitrate is in its hydrated form.