15.
Find the area of a triangle with a base of 9.3 ft. and the height is 3.5 ft.
32.55 ft²
24.81 ft²
16.275 ft²
11.0 ft²
16.
Find the area of a parallelogram with a base of 15 in. and the height is 7 in.
105 in²
110 in²
52.5 in²
210 in²
17.
Find the area of a trapezoid with bases of 9 mm and 16 mm, and the height is 4.5 mm.
112.5 mm²
72 mm²
40.5 mm²
56.25 mm²
My answers:
15. 16.275 ft²
16. 105 in²
17. 56.25 mm²
56.25
Yes, for 1#, 16.275 is the correct answer
To find the area of a triangle, you can use the formula: A = (1/2) * base * height. Let's apply this formula to the first question.
15. Given a base of 9.3 ft and a height of 3.5 ft, plug the values into the formula:
A = (1/2) * 9.3 ft * 3.5 ft
A = 4.65 ft * 3.5 ft
A = 16.275 ft²
So the area of the triangle is 16.275 ft².
Now let's move on to the second question about finding the area of a parallelogram.
To find the area of a parallelogram, you multiply the base by the height: A = base * height.
16. Given a base of 15 in and a height of 7 in, plug the values into the formula:
A = 15 in * 7 in
A = 105 in²
Therefore, the area of the parallelogram is 105 in².
For the third question about finding the area of a trapezoid, we need to use the formula: A = (1/2) * (b1 + b2) * h, where b1 and b2 are the lengths of the bases, and h is the height.
17. Given bases of 9 mm and 16 mm, and a height of 4.5 mm, plug the values into the formula:
A = (1/2) * (9 mm + 16 mm) * 4.5 mm
A = (1/2) * 25 mm * 4.5 mm
A = 56.25 mm²
Therefore, the area of the trapezoid is 56.25 mm².
Hence, the answers to the questions are:
15. 16.275 ft²
16. 105 in²
17. 56.25 mm²