How do i figure this?

State whether the following compound contain polar covalent bonds, non-polar covalent bonds, or ionic bonds, based on their electronegativities.

1)KF_________

Look up the electronegativity values for K and F and make your decision. We shall be happy to check your work. If there is something you don't understand about this question please post and we shall try to help you over the rough spots.

To figure out whether the compound KF contains polar covalent bonds, non-polar covalent bonds, or ionic bonds based on electronegativities, you need to compare the electronegativity values of the atoms involved.

Electronegativity is a measure of an atom's ability to attract electrons towards itself in a covalent bond. The difference in electronegativity between two atoms can help determine the type of bond they form.

The electronegativity values for potassium (K) and fluorine (F) can be found using a periodic table or an electronegativity chart.

K: Electronegativity ≈ 0.8 (Pauling scale)
F: Electronegativity ≈ 3.98 (Pauling scale)

To make the decision:

1. If the electronegativity difference is 0, the bond is considered non-polar covalent.
2. If the electronegativity difference is between 0 and 1.7, the bond is considered polar covalent.
3. If the electronegativity difference is greater than 1.7, the bond is considered ionic.

Now, compare the electronegativity values for K and F.

The electronegativity difference for KF is:

3.98 - 0.8 = 3.18

Since the electronegativity difference between K and F is greater than 1.7, the bond in KF is considered ionic. Therefore, KF contains ionic bonds.

Remember, it's important to double-check these values using a reliable source such as a periodic table or electronegativity chart, as values can slightly vary depending on the scale being used.