five consecutive multiples of 5 add up to 425. What is the largest number?
x+x+5+x+10+x+15+x+20 = 425
5x+50=425
x=75
x+20 = 95
answer = 95
To find the largest number among five consecutive multiples of 5 that add up to 425, we can use algebra to solve the problem.
Let's assume the smallest number in the sequence is x. Since they are consecutive multiples of 5, the other four numbers would be x+5, x+10, x+15, and x+20.
The sum of these five numbers is given by the equation:
x + (x+5) + (x+10) + (x+15) + (x+20) = 425
Simplifying this equation, we have:
5x + 50 = 425
Subtracting 50 from both sides:
5x = 375
Dividing both sides by 5:
x = 75
Therefore, the smallest number in the sequence is 75. And the largest number would be:
x + 20 = 75 + 20 = 95
So, the largest number among the five consecutive multiples of 5 is 95.