CONCENTRATION OF NaClO IN COMMERCIAL BLEACH.
Bleach comes as 6%(mass/volume) solution of NaClO. Calculate the Molarity of NaClO in bleach to three significant figures ( you need molar mass of NaClO)
To calculate the molarity of NaClO in bleach, we first need to determine the molar mass of NaClO.
The molar mass of NaClO can be calculated by summing the atomic masses of its constituent elements.
So, the molar mass of Na (sodium) is 22.99 g/mol, the molar mass of Cl (chlorine) is 35.45 g/mol, and the molar mass of O (oxygen) is 16.00 g/mol.
Adding these atomic masses together, we get:
Molar Mass of NaClO = (1 x Molar mass of Na) + (1 x Molar mass of Cl) + (1 x Molar mass of O)
= (1 x 22.99 g/mol) + (1 x 35.45 g/mol) + (1 x 16.00 g/mol)
= 74.44 g/mol
Now, let's calculate the molarity of NaClO in bleach.
Given that bleach is a 6% (mass/volume) solution of NaClO, we can assume that 6 g of NaClO is present in 100 mL (or 0.1 L) of bleach.
To convert the mass of NaClO to moles, we use the following formula:
Number of moles = Mass / Molar mass
So, the number of moles of NaClO present in 0.1 L of bleach is:
Number of moles = 6 g / 74.44 g/mol
≈ 0.0806 mol
Finally, to calculate the molarity (M) of NaClO in bleach, we use the formula:
Molarity = Number of moles / Volume (in liters)
Molarity = 0.0806 mol / 0.1 L
= 0.806 mol/L
Therefore, the molarity of NaClO in bleach is approximately 0.806 mol/L, rounded to three significant figures.