Tristen mixes nuts that cost $2.00 per pond with nuts that cost $4.00 per pound. He buys triple as much of the $2.00 per pound nut than he buys of the $4.00 per pound nut. If he spent a total of $32.00, how many pounds of the $2.00 per pound nut did he buy?
Let x = the amount of $2/lb nuts
Let y = the amount of the $4/lb nuts
He buys triple of x amount so
3y = x
This is similar to the first problem you posted. We need to know the value:
Our second equation is 2x+ 4y = 32
You can complete this one just like the previous one that you posted.
Let's suppose Tristen buys x pounds of the $2.00 per pound nuts.
According to the given information, Tristen buys triple as much of the $2.00 per pound nut than he buys of the $4.00 per pound nut. So, Tristen buys x/3 pounds of the $4.00 per pound nuts.
The cost of the $2.00 per pound nuts is $2.00 multiplied by x pounds, which is 2x dollars.
The cost of the $4.00 per pound nuts is $4.00 multiplied by x/3 pounds, which is 4(x/3) dollars or (4/3)x dollars.
The total cost of nuts is $32.00.
So, we can write the equation: 2x + (4/3)x = 32.
To solve this equation, we can simplify it: (6/3)x + (4/3)x = 32.
Combining like terms, we get: (10/3)x = 32.
To isolate x, we'll multiply both sides by 3/10: x = (32 * 3/10).
Simplifying further, we have: x = 9.6.
Therefore, Tristen bought approximately 9.6 pounds of the $2.00 per pound nut.