A rock is thrown upward off a bridge. In 2sec. the rock passes you on the way down. In 3 more sec. it hits the water. How high is the bridge above the water and how high did the rock go above the bridge?

Can someone help me start his problem!?

A rock is thrown upward off a bridge. In 2sec. the rock passes you on the way down. In 3 more sec. it hits the water. How high is the bridge above the water and how high did the rock go above the bridge?

If it passes you on the way down in 2 seconds, it took 1 second to reach its peak height.
Vf = Vo - 32t = 0 = Vo - 32(1) making the initial upward velocity 32fps and the velocity when passing you the same 32fps.

The distance from you to the water is derived from d = Vot + 32t^2 = 32(3) + 16(3)^2 = 96 + 144 = 240 ft.

Of course! Let's break down the problem step by step.

To find the height of the bridge above the water, we can utilize the concept of free-fall motion.

Step 1: Establish the motion of the rock:
The rock is thrown upward, which means it moves against the force of gravity. As a result, it eventually reaches its highest point and then falls back down to the water. This motion can be divided into two parts: ascending and descending.

Step 2: Determine the time taken for the rock to pass you on the way down:
Since it takes 2 seconds for the rock to pass you, this means it took the same amount of time to ascend to its highest point. Therefore, the time it takes for the rock to reach its highest point is 2 seconds.

Step 3: Determine the total time it takes for the rock to hit the water:
Given that it takes an additional 3 seconds for the rock to hit the water after passing you, the total time from the initial throw to hitting the water is 2 seconds (time to reach highest point) + 3 seconds (time to hit the water) = 5 seconds.

Step 4: Calculate the height of the bridge above the water:
Using the concept of free-fall motion, we can determine the height of the bridge above the water. With the total time of 5 seconds, we can use the equation:
d = 1/2 * g * t^2
where d represents the distance, g is the acceleration due to gravity (approximately 9.8 m/s^2), and t is the time.

Substituting the values into the equation:
d = 1/2 * 9.8 m/s^2 * (5 s)^2

By solving this equation, you can find the height of the bridge above the water.

Step 5: Determine how high the rock went above the bridge:
To find how high the rock went above the bridge, we need to subtract the height of the bridge from the total distance the rock traveled. As the rock reached its highest point at the bridge level, the distance traveled above the bridge is equal to the height the rock went above the bridge.

Therefore, by subtracting the height of the bridge from the total distance obtained in Step 4, you can determine how high the rock went above the bridge.

I hope this breakdown helps you get started on solving the problem!