Missy and Mussy are very messy sisters. Their dresser drawer consists of 43 white socks, 2 black socks, 23 blue socks and 8 red socks. What is the minimum number of socks they must remove from the drawer to be certain they have four socks of the same color?

They might draw out 3 white, 2 black, 3 blue, and 3 red. After that, the 12th sock must be the same color as one of the others.

To find the minimum number of socks Missy and Mussy must remove from the drawer to be certain they have four socks of the same color, we need to consider the worst-case scenario for each color.

Let's evaluate each color separately:
- White socks: To ensure they have four white socks, the worst-case scenario would be if they remove all 43 white socks and still don't have four of the same color.
- Black socks: Since there are only 2 black socks, regardless of how many they remove, they won't have four black socks.
- Blue socks: Similar to the white socks, in the worst-case scenario, they would need to remove all 23 blue socks and still not have four of the same color.
- Red socks: If they remove 5 red socks, they would still be left with 3 red socks. However, if they remove just one more red sock, no matter which one it is, they will be certain to have four red socks.

Therefore, the minimum number of socks Missy and Mussy must remove from the drawer to be certain they have four socks of the same color is 5 (removing the 5 red socks).