I need to figure out how to solve this equation your help will be much appreciate:-)

√5(x-1.2)-√3x<5(x+1.1)

To solve this equation, you need to isolate the variable x. Let's break down the process step by step:

Step 1: Distribute the terms on the right side of the equation using the distributive property:
√5(x - 1.2) - √3x < 5x + 5.5

Step 2: Simplify each term on both sides of the equation:
√5x - √6 - √3x < 5x + 5.5

Step 3: Move all x terms to one side of the equation, and all non-x terms to the other side:
√5x - √3x - 5x < 5.5 + √6

Step 4: Combine like terms:
√5x - √3x - 5x < 5.5 + √6
(-4x - √3x) < 5.5 + √6

Step 5: Move the constant term to the other side of the equation:
-√3x < 5.5 + √6 + 4x

Step 6: Square both sides of the equation to eliminate the square root:
(-√3x)^2 < (5.5 + √6 + 4x)^2
3x < (5.5 + √6 + 4x)^2

Step 7: Expand and simplify the right side of the equation:
3x < 30.25 + 11√6 + 24x + 10x√6 + 16x^2 + 8√6x

Step 8: Rearrange the equation to have all terms on one side:
16x^2 - (3x + 34x + 10√6x) + (30.25 + 11√6) > 0

Step 9: Combine like terms:
16x^2 - 37x - 10√6x + 30.25 + 11√6 > 0

Step 10: Simplify the expression:
16x^2 - (37 + 10√6)x + (30.25 + 11√6) > 0

Now that we have simplified the equation, you can calculate the discriminant to determine the solutions. The discriminant is given by the formula: b^2 - 4ac.

In this case, a = 16, b = - (37 + 10√6), and c = 30.25 + 11√6.

Once you find the discriminant, you can use it to determine the type of solutions the quadratic equation will yield. If the discriminant is positive, there are two distinct real solutions. If the discriminant is zero, there is one repeated real solution. If the discriminant is negative, there are no real solutions.

After finding the solutions, you can check if they satisfy the original inequality.