20% of HNO3 reacts with 10g of Caco3 by weight then find the quantity of HNO3?
To find the quantity of HNO3, we can use the concept of percentage composition.
Step 1: Determine the molar mass of CaCO3 (calcium carbonate).
The molar mass of CaCO3 = atomic mass of Ca + atomic mass of C + 3*(atomic mass of O)
The atomic mass of Ca = 40.08 g/mol
The atomic mass of C = 12.01 g/mol
The atomic mass of O = 16.00 g/mol
Therefore, the molar mass of CaCO3 = 40.08 + 12.01 + 3*(16.00) = 100.09 g/mol.
Step 2: Calculate the moles of CaCO3 using its mass.
moles = mass / molar mass
moles of CaCO3 = 10 g / 100.09 g/mol = 0.0999 mol (approximately 0.1 mol)
Step 3: Determine the stoichiometry between HNO3 and CaCO3.
From the balanced chemical equation, we know that 1 mole of CaCO3 reacts with 2 moles of HNO3.
So, if 0.1 moles of CaCO3 react, it will require 2 * 0.1 = 0.2 moles of HNO3.
Step 4: Convert moles of HNO3 to grams using its molar mass.
The molar mass of HNO3 = 1.01 + 14.01 + 3*(16.00) = 63.01 g/mol
mass = moles * molar mass
mass of HNO3 = 0.2 mol * 63.01 g/mol = 12.6 g
Therefore, the quantity of HNO3 required to react with 10 g of CaCO3 is approximately 12.6 grams.