an aqueous solution contains 1 mol of S2O3 ions and this reduces 4 mol chlorine molecules.What is the sulphur containing product of this reaction?
Cl2 + 2e = 2Cl^-\
2S2O3^2- ==> S4O6^2- + 2e
S2O3^2- is thiosufate.
S4O6^2- is tetrathionate.
To determine the sulfur-containing product of the reaction, we need to first identify the reaction taking place between S2O3 ions and chlorine molecules.
Given that 1 mole of S2O3 ions (thiosulfate ions) is reducing 4 moles of chlorine molecules, we can write the following balanced redox equation:
2 S2O3²- + 4 Cl2 → S + 6 Cl- + 4 O2
From the balanced equation, we can see that the thiosulfate ions (S2O3²-) are oxidized, and chlorine molecules (Cl2) are reduced. The products of this reaction are sulfur (S) and chloride ions (Cl-). Therefore, the sulfur-containing product is simply "S".
Overall, the reaction is a redox reaction in which thiosulfate ions reduce chlorine molecules, resulting in the formation of sulfur.