Please show me the steps to solving this equation:-)

√5(x-1.2)-√3x<5(x-1)

Your help is greatly appreciated.

To solve the given equation √5(x-1.2) - √3x < 5(x-1), follow these steps:

Step 1: Begin by isolating the square roots on one side of the inequality sign. Add √3x to both sides to eliminate it from the left side.
√5(x-1.2) < 5(x-1) + √3x

Step 2: Distribute 5 to both terms within the parentheses on the right side.
√5(x-1.2) < 5x - 5 + √3x

Step 3: Move the term with the square root, √5(x-1.2), to the right side of the inequality by subtracting it from both sides.
0 < 5x - 5 + √3x - √5(x-1.2)

Step 4: Combine like terms on the right side, which means rearranging the terms to have the √3x and √5(x-1.2) together.
√3x - √5(x-1.2) < 5x - 5

Step 5: To simplify the equation, you can multiply the expression √5(x-1.2) by the conjugate of its denominator, √5(x-1.2) + √3x.
√3x - (√5(x-1.2))² < 5x - 5
√3x - 5(x-1.2) < 5x - 5

Step 6: Expand (√5(x-1.2))² by multiplying it with itself.
√3x - 5(x² - 2.4x + 1.44) < 5x - 5

Step 7: Remove brackets and collect like terms.
√3x - 5x² + 12x - 7.2 < 5x - 5

Step 8: Move all terms to one side of the inequality by subtracting 5x and adding 7.2 to both sides.
-5x² + 7x - 12.2 < 0

Step 9: Rearrange the inequality in descending order.
-5x² + 7x - 12.2 < 0

Now, the equation has been simplified to a quadratic inequality. You can solve it by finding its solutions or graphing the inequality on a number line.