I am doing a lab and I really need help!
I calculated that my snail traveled as his average speed of .136 cm/s, 1.36m/s, and 4896 m/hr.
Does that sound right?
Also I need help on another thing. My paper says Calculate how long it will take your snail to cross a sidewalk (2m) cross a road (20 m).
How would I figure that out?
Last thing.
It says, use your graph to compare average speed and the speed of an object along a path. Are they always that same? Give evidence by marking on a graph where speed over a 30 second interval is faster or slower than average speed.
What does that even mean???? I'm so confused!
Please help!
This is due soon!!!!
Thanks so much!
No. Please check to be sure that the snail travels at 0.136 centimeters per second.
0.136 cm/s = 0.000136 m/s
1 hour = 60 * 60 = 3600 seconds
3,600 * 0.000136 = 0.4896 m / hour
for part 1, consider that your average jet plane flies at about 600 mph
No way your snail goes 4896 mph.
I'd think that a snail probably travels about 0.136 cm/s
That's what I'd call a snail's pace.
Since that's hard to measure, try seeing how far it travels in 10 seconds.
You just forgot to include the decimals :) a snail dosen't go over 4000 mph! Use common sense before turning these things in. Once said a turtle went 50 mph on a test,,, silly me
Sure, I'd be happy to help you with your lab!
First, let's address your initial question about the calculated average speed of your snail. To verify if your calculations are correct, we can use the given values and unit conversions. Here's how we can check:
1. For the average speed of 0.136 cm/s, convert it to meters per second (m/s) by dividing by 100: 0.136 cm/s = 0.00136 m/s.
2. For the average speed of 1.36 m/s, there is no need for conversion since it is already in meters per second.
3. For the average speed of 4896 m/hr, we need to convert it to meters per second. Start by converting hours to seconds: 1 hour = 60 minutes = 60 seconds. Then, divide 4896 m by 3600 seconds to obtain the speed in m/s: 4896 m/hr = 1.36 m/s.
Based on these calculations, it seems like there might be an error in your first calculation. The correct average speed is 0.00136 m/s, not 0.136 cm/s. Therefore, please revise your answer accordingly.
Moving on to your second question about calculating the time it takes for your snail to cross a sidewalk and a road:
To calculate the time, we can use the formula: time = distance / speed. Follow these steps:
1. For the sidewalk: Divide the distance of 2 m by the average speed of your snail in meters per second. This will give you the time it takes for the snail to cross the sidewalk.
2. For the road: Divide the distance of 20 m by the average speed of your snail in meters per second. This will give you the time it takes for the snail to cross the road.
Be sure to use the corrected average speed we calculated earlier.
For your last question about using a graph to compare average speed and the speed of an object along a path:
The statement is asking you to compare the average speed of your snail with the actual speed it had at different points during its travel. A graph can help you visualize this comparison.
To do this, you would need to plot the time (x-axis) against the speed (y-axis) on a graph. The average speed would be a horizontal line since it remains constant. You can mark points on the graph where the speed during a 30-second interval is either faster or slower than the average speed.
To determine if the speed during a 30-second interval was faster or slower than the average speed, you can compare it visually to the horizontal line representing the average speed. If the plotted point is above the line, it means the speed was faster during that interval. If it's below the line, it means the speed was slower during that interval.
By marking these points on the graph, you will provide evidence to demonstrate whether the speed of the snail along its path is always the same as the average speed or not.
I hope this helps you with your lab! If you have any more questions, feel free to ask. Good luck!