Ethylene glycol (antifreeze) has a density of 1.11 {\rm g/cm^3}.What is the mass in G of 435mL of this liquid?
mass = density (g/mL) * volume (mL), so
1.11g/cm^3 * 435cm^3 = 482.85 g
To find the mass of a liquid, we need to multiply the density by the volume. In this case, the density of ethylene glycol is given as 1.11 g/cm³, and the volume is 435 mL.
However, we need to convert mL to cm³ before we can proceed with the calculation. Since 1 mL is equivalent to 1 cm³, the volume of 435 mL is also equal to 435 cm³.
Now we can calculate the mass using the formula:
Mass = Density x Volume
Plugging in the values, we have:
Mass = 1.11 g/cm³ x 435 cm³
Calculating the product:
Mass = 481.85 g
Therefore, the mass of 435 mL of ethylene glycol is 481.85 grams.