Use the quadratic formula to solve the equation
x^2-5x=-10
a = 1
b = -5
c = +10
x = [-b +/-(b^2-4ac)]/2a
Plug in the numbers. The answer will include imaginary numbers, since b^2 - 4ac is negative.
x = [-b +/- sqrt(b^2-4ac)]/2a
To solve the equation using the quadratic formula, we need to first rearrange the equation into standard quadratic form, which is in the form of "ax^2 + bx + c = 0". In this case, we already have the equation in this form.
The quadratic formula is:
x = (-b ± √(b^2 - 4ac)) / (2a)
By comparing the equation to the quadratic form, we can determine the values of a, b, and c:
a = 1
b = -5
c = -10
Now, we can substitute these values into the quadratic formula to find the solutions for x.
x = (-(−5) ± √((-5)^2 - 4(1)(-10))) / (2(1))
Simplifying further:
x = (5 ± √(25 + 40)) / 2
x = (5 ± √65) / 2
Thus, the solutions to the equation x^2 - 5x = -10 are x = (5 + √65) / 2 and x = (5 - √65) / 2.