The distance, d, in feet that an object falls in t seconds is modeled by the formula d=16t(2) if you dive from a height of 128 feet, how long will it take to hit the water? (answer may be in simplified radical form).
just solve
16t^2 = 128
t^2 = 8
t = √8 = 2√2
To find out how long it would take for the object to hit the water, we need to set the equation for distance, d, equal to the given height of 128 feet and solve for time, t.
Given:
d = 128 feet (height)
d = 16t^2 (distance formula)
Setting them equal to each other:
128 = 16t^2
Now, we can solve for t:
Divide both sides of the equation by 16:
128/16 = t^2
Simplify the equation:
8 = t^2
To isolate t, we take the square root of both sides of the equation:
√8 = √t^2
Which simplifies to:
2√2 = t
Therefore, it would take approximately 2√2 seconds for the object to hit the water from a height of 128 feet.