You are studying a large population of claims of which 396 are pink (t) and 557 are Tan (T). Tan clams are completely dominant over pink clams. Calculate the following:

1. The frequencies of each allele.

2. The expected genotypic frequencies.

3. The number of heterozygous clams that you would predict to be in this population.

4. The expected phenotypic frequencies.

5. Assume that conditions were just right and over the course of the season, 1245 new baby clams were born. If you assume that all of the Hardy-Weinberg conditions are met (no evoution is or has occurred), how many of these baby clams would you expect to be pink and how would you many would you expect to be tan?

TT+Tt= Phenotypic frequencies for tan

tt=Phenotypic frequency for pink

557/(557+396)=Phenotypic frequency for tan=0.58

1-0.58=Phenotypic/genotypic frequency for pink=0.42

(T+t)^2=TT+2Tt+tt=1

Plugging in 0.42 for the genotypic frequency for pink in the above equation,

TT+2Tt+0.42=1 rearrangement gives,

TT+2Tt=0.58

Since the genotypes for Tt outnumber the genotype for TT 2:1, let TT=x and Tt=2x and solve for x:

x+2x=0.58

3x=0.58
x=0.58/3=0.19

Since x=0.19, the genotypic frequency for TT is 0.19, and the genotypic frequency for Tt is 0.38

Since the genotypic frequency for Tt is 0.38, the % of clams heterozygous for the Tt in the population is 0.38*(953)=362

For the new generation, calculate the number of clams with either phenotypes by multiplying the phenotypic frequencies by the new population number

1245 claims*(0.42)=523 pink clams

1245 claims-523 pink clams=722 tan clams

The fourth line from the bottom should say

Since the genotypic frequency for Tt is 0.38, the NUMBER of clams heterozygous for the Tt in the population is 0.38*(953)=362

To answer the questions, we need to understand the principles of genetics and use some basic calculations. Let's go through each question step by step.

1. The frequencies of each allele:
In this case, we have only two alleles: pink (t) and tan (T). The frequency of an allele is the proportion of that allele in the population. To calculate the frequency of each allele, we can use the following formulas:

Frequency of allele t = Number of pink clams (t) / Total population size
Frequency of allele T = Number of tan clams (T) / Total population size

From the information given in the question, we know that there are 396 pink clams (t) and 557 tan clams (T). The total population size can be calculated as follows:

Total population size = Number of pink clams + Number of tan clams

2. The expected genotypic frequencies:
In a population following Hardy-Weinberg equilibrium, we can calculate the expected genotypic frequencies using the following formulas:

Expected frequency of TT = (Frequency of allele T)^2
Expected frequency of Tt = 2 * (Frequency of allele T) * (Frequency of allele t)
Expected frequency of tt = (Frequency of allele t)^2

3. The number of heterozygous clams:
The number of heterozygous individuals (Tt genotype) in the population can be estimated by multiplying the frequency of the Tt genotype by the total population size.

Number of Tt clams = Expected frequency of Tt * Total population size

4. The expected phenotypic frequencies:
Since tan clams (T) are completely dominant over pink clams (t), the expected phenotypic frequencies can be calculated as:

Expected frequency of tan clams = Expected frequency of TT + Expected frequency of Tt
Expected frequency of pink clams = Expected frequency of tt

5. Expectation for new baby clams:
To calculate the number of pink and tan baby clams assuming Hardy-Weinberg conditions, we can use the following formulas:

Expected number of pink baby clams = Expected frequency of pink clams * Total number of baby clams
Expected number of tan baby clams = Expected frequency of tan clams * Total number of baby clams

Using these calculations, we can now find the answers to each question.