A car traveling at 5.0 m/s accelerates at the rate of 0.8 m/s2 for an interval of 3.0 s. Find vf.
To find the final velocity (vf), we can use the formula for acceleration:
vf = vi + at
Where:
vf is the final velocity,
vi is the initial velocity,
a is the acceleration,
t is the time period.
Given:
vi = 5.0 m/s (initial velocity),
a = 0.8 m/s^2 (acceleration),
t = 3.0 s (time period).
Substituting the given values into the formula, we get:
vf = 5.0 m/s + (0.8 m/s^2)(3.0 s)
First, calculate the product of acceleration and time:
(0.8 m/s^2)(3.0 s) = 2.4 m/s
Now, substitute this value back into the formula:
vf = 5.0 m/s + 2.4 m/s
Adding these velocities together gives us:
vf = 7.4 m/s
Therefore, the final velocity (vf) of the car is 7.4 m/s.
To find the final velocity (vf) of the car, we can use the formula for acceleration:
vf = vi + at
Where:
- vf is the final velocity
- vi is the initial velocity
- a is the acceleration
- t is the time interval
Given:
- vi = 5.0 m/s (initial velocity)
- a = 0.8 m/s² (acceleration)
- t = 3.0 s (time interval)
Substituting the given values into the formula, we have:
vf = 5.0 m/s + (0.8 m/s²) * 3.0 s
First, we calculate the value inside the parentheses:
(0.8 m/s²) * 3.0 s = 2.4 m/s
Next, we add the calculated value to the initial velocity:
vf = 5.0 m/s + 2.4 m/s
vf = 7.4 m/s
Therefore, the final velocity (vf) of the car is 7.4 m/s.