A plastic rod is rubbed against a wool shirt,
thereby acquiring a charge of −4.9 µC.
How many electrons are transferred from
the wool shirt to the plastic rod? The elemental charge is 1.6 × 10^-19C.
have you considered dividing the total charge by the charge on an electron?
To determine the number of electrons transferred, we can use the relationship between charge and the number of electrons. We know that the charge acquired by the plastic rod is -4.9 µC. The elementary charge is 1.6 × 10^-19 C, which represents the charge of a single electron.
We can calculate the number of electrons transferred by dividing the total charge acquired by the rod by the elementary charge:
Number of electrons transferred = (charge acquired by the rod) / (elementary charge)
Now let's substitute the values into the equation:
Number of electrons transferred = (-4.9 × 10^-6 C) / (1.6 × 10^-19 C)
To simplify this, we can divide the numerator and denominator by 10^-19:
Number of electrons transferred ≈ (-4.9 / 1.6) × (10^-6 / 10^-19)
Number of electrons transferred ≈ -3.0625 × 10^13
Since the number of electrons cannot be negative, we take the absolute value:
Number of electrons transferred ≈ 3.0625 × 10^13
Therefore, approximately 3.0625 × 10^13 electrons are transferred from the wool shirt to the plastic rod.
To determine the number of electrons transferred from the wool shirt to the plastic rod, we can use the formula:
Q = ne
Where:
Q = charge acquired by the rod = -4.9 µC = -4.9 × 10^-6 C
n = number of electrons transferred
e = elementary charge = 1.6 × 10^-19 C
Now, rearrange the formula to solve for n:
n = Q / e
Substituting the given values:
n = (-4.9 × 10^-6 C) / (1.6 × 10^-19 C)
n ≈ -3.06 × 10^13 electrons
Approximately 3.06 × 10^13 electrons are transferred from the wool shirt to the plastic rod.