A block,mass 20kg,is pulled upwards by a force F along a plane inclined at 30 degree to the horizontal.it accelerate along the inclined plane at 2m.s-2. The surface of the inclined exert a friction force on the block calculate the component of the gravitational force exerted on the block parallel to the incline.
the component of the gravitational force exerted on the block parallel to the incline is Friction force and this is how you calculate it Fg||=Mg* Sin*theta
To find the component of the gravitational force exerted on the block parallel to the incline, we need to consider the forces acting on the block.
Let's break down the forces:
1. Gravitational force (Weight): The weight of the block acts vertically downwards. Its magnitude can be calculated using the formula: Weight = mass × gravity, where 'gravity' is the acceleration due to gravity (approximately 9.8 m/s^2). Therefore, Weight = 20 kg × 9.8 m/s^2 = 196 N.
2. Normal force (N): The normal force acts perpendicular to the plane and is equal in magnitude but opposite in direction to the component of the weight perpendicular to the plane. In this case, the plane is inclined at 30 degrees, so the normal force can be calculated using the formula: N = Weight × cos(angle), where 'angle' is the angle of inclination. Therefore, N = 196 N × cos(30 degrees) = 169.9 N.
3. Friction force (Ff): The friction force is a resistive force acting parallel to the incline and in the opposite direction to the motion of the block. It can be determined using the formula: Ff = coefficient of friction × Normal force, where the coefficient of friction depends on the characteristics of the surface. Since the coefficient of friction is not given in the question, we cannot calculate it precisely. However, let's assume that it is given as 0.2. Therefore, Ff = 0.2 × 169.9 N = 33.98 N.
Now, let's calculate the component of the gravitational force parallel to the incline:
The component of the gravitational force acting parallel to the incline can be found using the formula: Fg_parallel = Weight × sin(angle), where 'angle' is the angle of inclination. Therefore, Fg_parallel = 196 N × sin(30 degrees).
Using the sin(30 degrees) = 0.5, we can calculate:
Fg_parallel = 196 N × 0.5 = 98 N.
Therefore, the component of the gravitational force exerted on the block parallel to the incline is 98 N.
To calculate the component of the gravitational force exerted on the block parallel to the incline, we first need to find the gravitational force acting on the block.
Step 1: Calculate the gravitational force:
The gravitational force can be calculated using the formula:
Gravitational force = mass * acceleration due to gravity
Given that the mass of the block is 20 kg, and the acceleration due to gravity is approximately 9.8 m/s^2, we can calculate the gravitational force as follows:
Gravitational force = 20 kg * 9.8 m/s^2 = 196 N
Step 2: Determine the angle of the inclined plane:
The inclined plane is inclined at an angle of 30 degrees to the horizontal.
Step 3: Calculate the component of the gravitational force parallel to the incline:
The component of the gravitational force parallel to the incline can be calculated using the formula:
Force parallel to incline = Gravitational force * sin(angle of incline)
In this case, the angle of the incline is 30 degrees, so we can calculate the component as follows:
Force parallel to incline = 196 N * sin(30 degrees)
Force parallel to incline = 196 N * 0.5
Force parallel to incline = 98 N
Therefore, the component of the gravitational force exerted on the block parallel to the incline is 98 N.