An inductor used in a dc power supply has an inductance of 12 H and a resistance of 180 ohms and carries a current of .300 A. (a) How much energy is stored in the magnetic field? (b) At what rate is thermal energy developed in the inductor?
ok once again I got part (a) .540 J, but I am confused on part (b) again! Help please!
b. P = I^2 x R = 16.2 watts
To calculate the rate at which thermal energy is developed in the inductor (part b), we need to use the formula for power (P) in an electrical circuit. The formula for power is given by:
P = I^2 * R
Where:
P is the power in watts (W)
I is the current in amperes (A)
R is the resistance in ohms (Ω)
In this case, we already know the values for the current and resistance, which are both given in the question. Plugging in these values:
P = (0.300 A)^2 * 180 Ω
P = 0.09 A^2 * 180 Ω
P = 16.2 W
Therefore, the rate at which thermal energy is developed in the inductor is 16.2 watts (W).