Median family income in country x between 1990 and 1999 can be modeled by f(x)=1144.7(x-1990)+35,834 where x is the year. Determine the median income was $42,303.
I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834
.177=x-1990
The median income was $1144.7 every year
Thanks for all your help:-)
F(x) = 1144.7(x-1990) + 35,834 = $42303.
1144.7x for y - 2277953 + 35834 = 42303
1144.7x - 2242119 = 42303
1144.7x = 2284422
X = 1995.65 or 1996.
The Median income was $42,303 for year
1996.
To determine the year when the median income was $42,303, you need to solve for x in the equation:
f(x) = 1144.7(x-1990) + 35,834
Set f(x) equal to the given median income:
42,303 = 1144.7(x-1990) + 35,834
To solve for x, let's start by subtracting 35,834 from both sides:
42,303 - 35,834 = 1144.7(x-1990)
6,469 = 1144.7(x-1990)
Next, divide both sides by 1144.7:
6,469 / 1144.7 = x - 1990
Simplifying, we get:
5.653 = x - 1990
Finally, to isolate x, add 1990 to both sides:
5.653 + 1990 = x
1995.653 = x
Therefore, the median income of $42,303 was reached in the year 1995.
To determine the year when the median income was $42,303, you need to solve the equation:
42,303 = 1144.7(x - 1990) + 35,834
Let's solve it step by step:
1. First, subtract 35,834 from both sides of the equation:
42,303 - 35,834 = 1144.7(x - 1990)
This simplifies to:
6,469 = 1144.7(x - 1990)
2. Divide both sides of the equation by 1144.7:
6,469 / 1144.7 = x - 1990
This simplifies to:
5.65 = x - 1990
3. Add 1990 to both sides of the equation:
5.65 + 1990 = x
This simplifies to:
1995.65 = x
Therefore, the median family income was $42,303 in the year 1995.