# college algebra

Median family income in country x between 1990 and 1999 can be modeled by f(x)=1144.7(x-1990)+35,834 where x is the year. Determine the median income was \$42,303.

I did it this way don't know if it's right
f(x)=1144.7(x-1990)+35,834
42,303-35,834 = 1144.7 - (x-1990) + 35,834
6469. 1144 7 - (x-1990). 35,834

.177=x-1990
The median income was \$1144.7 every year

1. 0
2. 0
1. F(x) = 1144.7(x-1990) + 35,834 = \$42303.
1144.7x for y - 2277953 + 35834 = 42303
1144.7x - 2242119 = 42303
1144.7x = 2284422
X = 1995.65 or 1996.

The Median income was \$42,303 for year
1996.

posted by Henry

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