What is the concentration of methanol in a solution prepared by combining 7.85mL of a 3.693M methanol solution with 17.50mL of water? Assume volumes are additive and report your answer to 3 decimal places.
3.693M methanol x (7.85/(7.85+17.50) = ?
To find the concentration of methanol in the solution, we need to calculate the amount of methanol present in the combined volume and then divide it by the total volume of the solution.
First, let's calculate the amount of methanol in the 7.85 mL of the 3.693 M methanol solution.
Amount of methanol = volume × concentration
Amount of methanol = 7.85 mL × 3.693 M
Amount of methanol = 28.988 mL·M
Next, let's calculate the total volume of the solution.
Total volume = volume of methanol + volume of water
Total volume = 7.85 mL + 17.50 mL
Total volume = 25.35 mL
Now, let's find the concentration of methanol in the solution by dividing the amount of methanol by the total volume of the solution.
Concentration = Amount of methanol / Total volume
Concentration = 28.988 mL·M / 25.35 mL
Concentration = 1.142 M
So, the concentration of methanol in the solution prepared by combining 7.85 mL of a 3.693 M methanol solution with 17.50 mL of water is 1.142 M.