Thato caught 4 snails and placed them all in the same small circle on the ground and organised a race......1st snail travelled 24cm in 4minutes,2nd snail travelled 35 cm in 7minutes,3rd snail travelled 33cm in 5minutes and the 4th snail travelled 39cm in 6minutes..... (1)how far would the second snail travel in 1h10min?
How long would it take the 4th snail to travel 1km?
2nd snail goes 35 cm in 7 minutes
so 35/7 in 1 minute, so
In 1 minute it goes 5 cm
then in 1 hr, 10 or 70 minutes it would got
70(5) or 350 cm
4th snail:
39 cm in 6 minutes
100 cm in (6/39)(100) = 600/39 minutes
or 1 m in 600/39 minutes
1000 m in 600000/39 minutes
1 km in 15384.6 min = 256 hours, 25 minutes.
Why is all the other data given?
To find out how far the second snail would travel in 1 hour and 10 minutes, you can calculate its average speed and then multiply it by the duration.
Let's start by calculating the average speed of the second snail. We can use the formula:
Average Speed = Total Distance / Total Time
For the second snail, the total distance is given as 35 cm, and the total time is given as 7 minutes. Therefore,
Average Speed = 35 cm / 7 minutes = 5 cm/minute
Now, let's convert 1 hour and 10 minutes into minutes. We know that 1 hour equals 60 minutes. Therefore,
1 hour and 10 minutes = 1 hour (60 minutes) + 10 minutes = 70 minutes.
Finally, we can calculate the distance traveled by the second snail in 1 hour and 10 minutes by multiplying the average speed by the duration.
Distance Traveled = Average Speed * Duration
Distance Traveled = 5 cm/minute * 70 minutes.
Calculating this value, we get:
Distance Traveled = 350 cm.
Therefore, the second snail would travel 350 cm (or 3.5 meters) in 1 hour and 10 minutes.