a shot putter put the shoot with an initial velocity of 25m/s at an angle of 32 degree from the horizontal. determine the horizontal and vertical velocity of the shoot
Initial vertical velocity = 25 sin32
= 13.25 m/s
This component becomes less during the flight of the shot, as gravity accelerates it downward.
Horizontal velocity = 25 cos32 = 21.20 m/s
To determine the horizontal and vertical velocities of the shot put, we can use trigonometry.
Given:
Initial velocity (v₀) = 25 m/s
Launch angle (θ) = 32 degrees
The horizontal velocity (v_horizontal) remains constant throughout the projectile motion, while the vertical velocity (v_vertical) changes due to the effect of gravity.
To find the horizontal velocity:
v_horizontal = v₀ * cos(θ)
v_horizontal = 25 m/s * cos(32°)
v_horizontal ≈ 21.35 m/s (rounded to two decimal places)
To find the vertical velocity:
v_vertical = v₀ * sin(θ)
v_vertical = 25 m/s * sin(32°)
v_vertical ≈ 13.54 m/s (rounded to two decimal places)
Therefore, the horizontal velocity of the shot put is approximately 21.35 m/s, and the vertical velocity is approximately 13.54 m/s.