How much energy would be needed to warm 1.5 L of water from 25 °C to 50 °C? The specific heat capacity of water is 4186 J/kg/°C.
A liter is 1 kilogram of water
4186 J /(kg degC) * (50-25)deg C * 1 kg
= 104,650 Joules
To calculate the energy needed to warm a given amount of water, you can use the formula:
Q = mcΔT
Where:
Q is the energy needed,
m is the mass of water,
c is the specific heat capacity of water, and
ΔT is the change in temperature.
In this case, you are given the specific heat capacity of water (c) as 4186 J/kg/°C. However, you need to find the mass of water (m) first.
To find the mass of water, you need to use the density formula:
Density = mass/volume
The density of water is approximately 1 kg/L. Therefore, the mass of 1.5 L of water would be:
Mass = 1.5 L * 1 kg/L = 1.5 kg
With the mass of water now known, you can calculate the energy required to warm the water:
Q = mcΔT = 1.5 kg * 4186 J/kg/°C * (50 °C - 25 °C)
Simplifying the equation:
Q = 1.5 kg * 4186 J/kg/°C * 25°C
Q = 156,525 J
Therefore, the amount of energy needed to warm 1.5 L of water from 25 °C to 50 °C is approximately 156,525 J (Joules).