#2.) Draw a free body diagram for the following situation:
a.) A 0.15 kg running shoe is pushed to the right, with a constant velocity, across a wet concrete floor with an applied force of 3.5 N.
b.) Calculate the normal force exerted by the concrete onto the running shoe.
a.) To draw a free body diagram, we need to identify all the forces acting on the object and represent them as vectors. In this situation, the forces acting on the running shoe are:
1. Applied force (F_applied): This is the force applied to the right, with a magnitude of 3.5 N.
2. Weight (mg): The weight of the shoe acts downward, with a force equal to the product of mass (0.15 kg) and acceleration due to gravity (9.8 m/s^2).
Since the shoe is moving with a constant velocity, there is no acceleration, which means the net force is zero. This implies that the applied force is balanced by the force of friction. In this case, the frictional force is not required to be shown in the free body diagram.
b.) To calculate the normal force exerted by the concrete, we need to consider that the shoe is on a horizontal surface, and the normal force acts perpendicular to it. In this case, the normal force is equal in magnitude and opposite in direction to the weight of the shoe.
Using the equation F_N = mg, we can calculate the normal force:
F_N = 0.15 kg x 9.8 m/s^2 = 1.47 N
Therefore, the normal force exerted by the concrete onto the running shoe is 1.47 N.