A 1500.0 kg car accelerates uniformly to double its speed from 35.9 km/h in 4.74 s. What net force acted on this car?
5104
To find the net force acting on the car, we can use Newton's second law of motion, which states that the net force (F) acting on an object is equal to the mass (m) of the object multiplied by its acceleration (a). In this case, we need to find the acceleration first.
Given:
Mass of the car (m) = 1500.0 kg
Initial speed (u) = 35.9 km/h
Final speed (v) = double the initial speed = 2 * 35.9 km/h
Time taken (t) = 4.74 s
First, we need to convert the speeds from km/h to m/s since the SI unit for acceleration is in m/s².
1 km/h = 1000/3600 = 5/18 m/s
So, the initial speed (u) = 35.9 km/h * (5/18) m/s = 10.0 m/s.
Since the car is accelerating uniformly, we can use the equation of motion:
v = u + at,
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.
Rearranging the equation, we have:
a = (v - u) / t = (2 * 10.0 m/s - 10.0 m/s) / 4.74 s = 10.0 m/s / 4.74 s = 2.109 m/s².
Now, we can use Newton's second law to calculate the net force:
F = m * a = 1500.0 kg * 2.109 m/s² = 3163.5 N.
Therefore, the net force acting on the car is 3163.5 N.