A cylindrical tube is open at both ends.the internal diameter tube 10.4cm and its length is 25cm. If the thickness of the tube 8mm everywhere,find the total surface of area of the tube.
inner diameter is 10.4
outer diameter is 11.2
A = π(25)(10.4+11.2) = 540π
Bt its ans is 1816.32cm^2
TOTAL SURFACE AREA =
EXTERNAL CURVED SURFACE AREA INTERNAL CURVED SURFACE AREA
in AREA OF BOTH CROSS SECTION
=2¦ÐRh 2¦Ðrh 2¦Ð{R square - r square)
To find the total surface area of the tube, we need to find the areas of the two circular ends and the curved surface area of the tube.
First, let's find the radius of the internal diameter of the tube. The internal diameter is given as 10.4 cm, so the internal radius (r) is half of the diameter, which is 10.4/2 = 5.2 cm.
Next, let's find the radius of the external diameter of the tube. The thickness of the tube is 8 mm everywhere, so the external radius (R) is the sum of the internal radius (r) and the thickness (t). Therefore, R = 5.2 + 0.8 = 6 cm.
Now, let's calculate the areas:
1. The area of each circular end of the tube is given by the formula A1 = π R^2. (Since the tube is open at both ends, we have two circular ends.)
A1 = 2 * π * (6 cm)^2
2. The curved surface area of the tube is given by the formula A2 = 2πRl, where l is the length of the tube.
A2 = 2 * π * 6 cm * 25 cm
Finally, we can find the total surface area of the tube by summing the areas of the two circular ends and the curved surface area:
Total Surface Area = A1 + A2
I will now calculate the values for you.