a .50 g of NaCl is added to water to create a .50 L solution. what volume of this solution is needed to create a 1.30L solution that is .100M NaCl
50g of NaCl*(1 mole of NaCl/58.44g of NaCl)=moles of NaCl
Molarity =moles of NaCl/0.50L
Once you calculate the molarity using the setup, use M1V1=M2V2 to calculate the volume needed.
M1=moles of NaCl/0.50L
V1=?
M2=0.100M
V2=1.30L
Plug in and solve
V1=(M2/M1)V2
To determine the volume of the 0.100 M NaCl solution that can be made from the 0.50 g NaCl and water, we need to consider the molar mass of NaCl and the relationship between moles, concentration, and volume.
1. Calculate the number of moles of NaCl:
Mass of NaCl = 0.50 g
Molar mass of NaCl = 58.44 g/mol (sodium = 22.99 g/mol, chloride = 35.45 g/mol)
Moles of NaCl = Mass of NaCl / Molar mass of NaCl
= 0.50 g / 58.44 g/mol
≈ 0.00855 mol
2. Determine the volume of the 1.30 L solution:
Volume of the 1.30 L solution = 1.30 L
3. Calculate the concentration of NaCl in the 1.30 L solution:
Concentration (Molarity) = Moles / Volume
= 0.00855 mol / 1.30 L
≈ 0.00658 M
4. Use the concentration of the desired solution to find the volume needed:
Concentration (Molarity) = Moles / Volume
Rearrange the equation to solve for volume:
Volume = Moles / Concentration
Volume = 0.00855 mol / 0.00658 M
≈ 1.30 L
Therefore, the volume of the 0.100 M NaCl solution that can be made from the 0.50 g NaCl and water is approximately 1.30 L, which is the same as the desired 1.30 L solution volume.
To find the volume of the .100 M NaCl solution, we need to calculate the number of moles of NaCl required and then use the molarity equation to determine the volume of the solution. Here are the steps:
1. Calculate the number of moles of NaCl required:
Number of moles = Mass of NaCl / Molar mass of NaCl
Given: Mass of NaCl = 0.50 g
The molar mass of NaCl = 22.99 g/mol (sodium) + 35.45 g/mol (chlorine)
Molar mass of NaCl = 58.44 g/mol
Number of moles = 0.50 g / 58.44 g/mol
2. Use the molarity equation to find the volume of the solution:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Rearrange the equation to solve for the volume:
Volume of solution (in liters) = Moles of solute / Molarity
Given: Molarity = 0.100 M
Moles of solute = calculated in step 1
Volume of solution = Moles of solute / Molarity
Volume of solution = (0.50 g / 58.44 g/mol) / 0.100 M
Now, calculate the volume of the solution needed to create a 1.30 L solution:
Volume of solution = (0.50 g / 58.44 g/mol) / 0.100 M
Multiply the result by 1.30 L to find the volume needed for a 1.30 L solution.
Please perform the calculations to get the final answer.