A coin of mass 3 g slides horizontally on the surface of a table. The frictional force exerted on the penny is 0.0147 N. What is the coefficient of friction between the table and the penny?

0.0147=Fn(µk)= (3kg)(9.8m/s^2)µk,

Solve for µk

0.0147 = 0.003*g*(µk)

µk = 0.50

Devron forgot to convert mass to kg.

Read it wrong. Thought mass was already given in Kg

To find the coefficient of friction between the table and the penny, we can use the formula:

Coefficient of friction (μ) = Frictional force (F) / Normal force (N)

The frictional force exerted on the penny is given as 0.0147 N. However, we need to find the normal force first.

The normal force is the force exerted by the table on the coin perpendicular to the surface of the table. It is equal in magnitude but opposite in direction to the force exerted by the penny on the table due to gravity.

Since the coin is not accelerating vertically, the net force in the vertical direction is zero. This means that the force of gravity (weight) and the normal force must be equal in magnitude:

Weight (mg) = Normal force (N)

The mass of the penny is given as 3 g, which is 0.003 kg (converting grams to kilograms).

Now, we can find the normal force using the formula:

Normal force (N) = Weight (mg)

Substituting the values, we have:

N = 0.003 kg * 9.8 m/s^2 = 0.0294 N

Now that we have found the normal force, we can find the coefficient of friction:

μ = F / N = 0.0147 N / 0.0294 N = 0.5

Therefore, the coefficient of friction between the table and the penny is 0.5.