if we mix 25 grams of sodium bromide with a large amount of potassium chloride, what will our theoretical yield of sodium chloride be?
0%. They don't react. Sorry about that.
To determine the theoretical yield of sodium chloride, we need to calculate the possible chemical reaction between sodium bromide (NaBr) and potassium chloride (KCl). The reaction equation is as follows:
NaBr + KCl -> NaCl + KBr
By comparing the stoichiometric coefficients in the reaction equation, we can conclude that for every 1 mole of NaBr reacted, 1 mole of NaCl is produced.
To calculate the theoretical yield of sodium chloride, we can follow these steps:
Step 1: Convert the given mass of NaBr into moles.
To do this, we need the molar mass of NaBr, which is the sum of the atomic masses of sodium (Na) and bromine (Br).
Molar mass of NaBr = (1 * atomic mass of Na) + (1 * atomic mass of Br)
= (1 * 22.99 g/mol) + (1 * 79.90 g/mol)
= 102.89 g/mol
Now, we can convert the given mass of NaBr into moles using the molar mass.
Moles of NaBr = Mass of NaBr / Molar mass of NaBr
= 25 g / 102.89 g/mol
≈ 0.2431 mol
Step 2: Calculate the moles of NaCl produced.
Since the reaction is 1:1, the number of moles of NaCl produced will be the same as the moles of NaBr used.
Moles of NaCl = 0.2431 mol
Step 3: Convert the moles of NaCl into grams.
Using the molar mass of NaCl, we can convert the moles into grams.
Molar mass of NaCl = (1 * atomic mass of Na) + (1 * atomic mass of Cl)
= (1 * 22.99 g/mol) + (1 * 35.45 g/mol)
= 58.44 g/mol
The theoretical yield of sodium chloride can be calculated as follows:
Theoretical yield of NaCl = Moles of NaCl * Molar mass of NaCl
= 0.2431 mol * 58.44 g/mol
≈ 14.19 g
Therefore, the theoretical yield of sodium chloride would be approximately 14.19 grams.
To determine the theoretical yield of sodium chloride when mixing sodium bromide with potassium chloride, we need to consider the balanced equation for the reaction between these two compounds.
The balanced equation is:
2 NaBr + KCl -> 2 KBr + NaCl
From the equation, it can be seen that two moles of sodium bromide react to form two moles of potassium bromide and one mole of sodium chloride.
Now, let's calculate the moles of sodium bromide using the given mass of 25 grams:
Molar mass of NaBr = 22.99 g/mol + 79.90 g/mol = 102.89 g/mol
Moles of NaBr = Mass / Molar mass
Moles of NaBr = 25 g / 102.89 g/mol = 0.243 moles (approx.)
According to the balanced equation, 2 moles of NaBr produce 1 mole of NaCl. Therefore, the moles of NaCl can be calculated as:
Moles of NaCl = Moles of NaBr / 2
Moles of NaCl = 0.243 moles / 2 = 0.122 moles (approx.)
Finally, we can find the theoretical yield of NaCl in grams using the molar mass of sodium chloride:
Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol
Theoretical yield of NaCl = Moles of NaCl * Molar mass of NaCl
Theoretical yield of NaCl = 0.122 moles * 58.44 g/mol = 7.13 grams (approx.)
Hence, the theoretical yield of sodium chloride would be approximately 7.13 grams.