Calculate the theoretical yield of MnO3 when 2.0 moles of Mn react with 2.0 moles O2. Write a balanced equation for the reation.
To calculate the theoretical yield of MnO3, we first need to write a balanced equation for the reaction between Mn and O2. The balanced equation will give us the stoichiometric ratio of reactants and products, which we can use to calculate the theoretical yield.
The balanced equation for the reaction is:
2 Mn + 3 O2 → 2 MnO3
From the balanced equation, we can see that 2 moles of Mn react with 3 moles of O2 to produce 2 moles of MnO3. Therefore, the stoichiometric ratio between MnO3 and Mn is 2:2, or 1:1.
Given that we have 2.0 moles of Mn, we can determine the theoretical yield of MnO3 by using the stoichiometric ratio:
Theoretical yield of MnO3 = 2.0 moles of Mn * (1 mole of MnO3 / 2 moles of Mn)
The moles of Mn cancel out, leaving us with:
Theoretical yield of MnO3 = 2.0 moles of MnO3 / 2
Simplifying the equation, we get:
Theoretical yield of MnO3 = 1.0 moles of MnO3
Therefore, the theoretical yield of MnO3 when 2.0 moles of Mn react with 2.0 moles of O2 is 1.0 moles of MnO3.