PHYSICS

A copper wire and an aluminium wire have length's in the ratio 3:2.diameters n the ratio 2:3 AND FORCES APPLIED IN THE RATIO 4:5 find the ratio of increase in length of the two wires.(Y FOR COPPER =1.1*1O^11
N/m^2,Y for aluminum=0.70*10^11 N/m^2).
ans:
1)189:110

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  1. X = Length increase = L*Force/(Area)(Y)

    Y is Young's modulus

    X(copper)/X(aluminum) = (3/2)*(4/5)/[(2/3)^2*(1.1/.7]
    = 1.718
    which happens to equal 189/110

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